JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    Minimum number of times a fair coin must be tossed so that the probability of getting at least one head is more than 99% is : [JEE Main 10-4-2019 Afternoon]

    A) 5                                 

    B) 6

    C) 7

    D) 8

    Correct Answer: C

    Solution :

     \[1-{{\left( \frac{1}{2} \right)}^{n}}>\frac{99}{100}\]\[\Rightarrow {{\left( \frac{1}{2} \right)}^{n}}<\frac{1}{100}\]\[\Rightarrow n=7.\]                       


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