A) \[-0.4{{\Delta }_{o}}\] and \[-0.8{{\Delta }_{t}}\]
B) \[-0.4{{\Delta }_{o}}\]and \[-1.2{{\Delta }_{t}}\]
C) \[-2.4{{\Delta }_{o}}\] and \[-1.2{{\Delta }_{t}}\]
D) \[-0.6{{\Delta }_{o}}\] and \[-0.8{{\Delta }_{t}}\]
Correct Answer: A
Solution :
\[[Fe{{({{H}_{2}}O)}_{6}}]C{{l}_{2}},F{{e}^{2+}}\to 3{{d}^{6}}\to {{({{t}_{2g}})}^{4}}{{({{e}_{g}})}^{2}}\] \[C.F.S.E.=4\times (-0.4{{\Delta }_{o}})+2\times 0.6{{\Delta }_{o}}=-0.4{{\Delta }_{o}}\]\[{{K}_{2}}[NiC{{l}_{4}}],N{{i}^{2+}}\to 3{{d}^{8}}\to {{(e)}^{4}}{{({{t}_{2}})}^{4}}\] \[C.F.S.E.=4\times (-0.6{{\Delta }_{t}})+4\times (0.4{{\Delta }_{t}})=-0.8{{\Delta }_{t}}\]
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