JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    Space between two concentric conducting spheres of radii a and \[b\left( b>a \right)\] is filled with a medium of resistivity\[\rho \]. The resistance between the two spheres will be : [JEE Main 10-4-2019 Afternoon]

    A) \[\frac{\rho }{4\pi }\left( \frac{1}{a}-\frac{1}{b} \right)\]    

    B) \[\frac{\rho }{2\pi }\left( \frac{1}{a}-\frac{1}{b} \right)\]

    C) \[\frac{\rho }{2\pi }\left( \frac{1}{a}+\frac{1}{b} \right)\]              

    D) \[\frac{\rho }{4\pi }\left( \frac{1}{a}+\frac{1}{b} \right)\]

    Correct Answer: A

    Solution :

    \[dR=\rho .\frac{dx}{4\pi {{x}^{2}}}\]           \[\int_{{}}^{{}}{dR}=\rho .\int\limits_{a}^{b}{\frac{dx}{4\pi {{x}^{2}}}}\]           \[R=\frac{\rho }{4\pi }\left[ -\frac{1}{x} \right]_{a}^{b}\]           \[R=\frac{\rho }{4\pi }\left( \frac{1}{a}-\frac{1}{b} \right)\]                      


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