A) Both are unstable
B) Both are stable
C) \[{{L}_{i2}}+\] is stable and \[{{L}_{i2}}-\] is unstable
D) \[{{L}_{i{{2}^{+}}}}\]is unstable and \[{{L}_{i2}}-\] is stable
Correct Answer: B
Solution :
\[L{{i}^{{{2}^{+}}}}\left( 5{{e}^{-}} \right)=\sigma 1{{s}^{2}},\sigma *1{{s}^{2}},\,\,\sigma \,2{{s}^{2}},\,\,\sigma \,*2{{s}^{2}}\,\] \[L{{i}_{{{2}^{-}}}}\text{ }\left( 7e- \right)\text{ }=\text{ }\sigma \,1{{s}^{2}},\text{ }\sigma *1{{s}^{2}},\text{ }\sigma \,2{{s}^{2}},\text{ }\sigma *2{{s}^{2}}\] Bond order of \[L{{i}_{{{2}^{+}}}}=0.5\] Bond order of \[L{{i}_{2-}}=0.5\] Both \[L{{i}_{{{2}^{+}}}}\]and \[L{{i}_{{{2}^{-}}}}\] has non-zero bond order and hence both are stable.
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