JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Morning)

  • question_answer
    A sample of radioactive material A, that has an activity of \[10\text{ }mCi(1\text{ }Ci=3.7\times {{10}^{10}}\,decays/s)\], has twice the number of nuclei as another sample of different radioactive material B which has an activity of \[20\text{ }mCi\]. The correct choices for half-lives of A and B would then be respectively: [JEE Main Online Paper (Held On 09-Jan-2019 Morning]

    A) 10 days and 40 days

    B) 20 days and 10 days

    C) 5 days and 10 days

    D) 20 days and 5 days

    Correct Answer: D

    Solution :

    \[\because \,\,\,\,A\,\,=\,\,\lambda N\] \[10\,\,=\,\,{{\lambda }_{A}}(2{{N}_{0}})\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,;\,\,20\,\,=\,\,{{\lambda }_{B}}{{N}_{0}}\] \[\Rightarrow \,\,\,\frac{1}{4}\,\,=\,\,\frac{{{\lambda }_{A}}}{{{\lambda }_{B}}}\,\,=\,\,\frac{{{({{\lambda }_{1/2}})}_{B}}}{{{({{\lambda }_{1/2}})}_{A}}}\] Ratio of half life for A arid B is 4 : 1 So, option is correct.


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