question_answer

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P, such that the block does not move downward? [JEE Main Online Paper (Held On 09-Jan-2019 Morning]

A) 32 N            

B) 25 N

C) 23 N            

D) 18 N

Correct Answer: A

Solution :

\[P+fr+3+mg\,\,\sin \,\,45{}^\circ \] \[P=\,\,3\,\,+\,\,\frac{100}{\sqrt{2}}\,\,-\,\,0.6\,\frac{100}{\sqrt{2}}\] \[P\,\,=\,\,3\,\,+\,\,\frac{40}{\sqrt{2}}\] \[=32\text{ }N\] Option is correct