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JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Evening)

  • question_answer
    If the tines \[x=ay+b,\]\[z=cy+d\]and \[x=a'z\,\,+b'\], \[y\,\,=\,\,c'z\,\,+d'\] are perpendicular then: [JEE Main Online Paper (Held On 09-Jan-2019 Evening]

    A) \[cc'+a+a'=0\]                          

    B)               \[aa'+c+c'=0\]

    C)               \[bb'+cc'+1=0\]                    

    D)               \[ab'+bc'+1=0\]

    Correct Answer: B

    Solution :

    Equation of 1st line is \[\frac{x-b}{a}\,\,=\,\,\frac{y}{1}\,\,=\,\,\frac{z-d}{c}\] Equation of 2nd line is \[\frac{x-b'}{a'}=\frac{y-b'}{c'}=\frac{z}{1}\] Lines are perpendicular so that \[aa'+\text{ }c+c=0\]


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