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JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Evening)

  • question_answer
    For the reaction, \[2A\,\,+\,\,B\,\,\to \] products, when the concentrations of A and B both were doubled, the rate of the reaction increased from \[0.3\text{ }mol\text{ }{{L}^{-1}}{{s}^{-}}^{1}\] to\[2.4\text{ }mol\text{ }{{L}^{-1}}{{s}^{-}}^{1}\]. When the concentration of A alone is doubled, the rate increased from \[0.3\text{ }mol\text{ }{{L}^{-}}^{1}\,{{s}^{-}}^{1}\] to\[0.6\text{ }mol\,\,L{{\,}^{-}}^{1}s{{\,}^{-1}}\]. Which one of the following statements is correct? [JEE Main Online Paper (Held On 09-Jan-2019 Evening]

    A) Order of the reaction with respect to A is 2.

    B) Total order of the reaction is 4.

    C) Order of the reaction with respect to B is 1.

    D) Order of the reaction with respect to B is 2.

    Correct Answer: D

    Solution :

    \[r=k{{\left[ A \right]}^{x}}{{\left[ B \right]}^{y}}\] \[8\,\,\propto \,\,{{\left( 2 \right)}^{x}}{{\left( 2 \right)}^{y}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,......(1)\] \[2\,\,\propto \,\,{{\left( 2 \right)}^{x}}~~~~~~~~....\left( 2 \right)\] \[\therefore \text{ }x=1~~~~~~~~~~~~y=2\] \[\therefore \] order w.r.t. B is two


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