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JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Evening)

  • question_answer
    Two Carnot engines A and B are operated in series. The first one, A, receives heat at \[{{T}_{1}}\left( =600\text{ }K \right)\] and rejects to a reservoir at temperature Ta. The second engine B receives heat rejected by the first engine and, in turn, rejects to a heat reservoir at\[{{T}_{3}}(=400\text{ }K)\]. Calculate the temperature \[{{T}_{2}}\] if the work outputs of the engines are equal: [JEE Main Online Paper (Held On 09-Jan-2019 Evening]

    A) 500K    

    B) 300K

    C) 600 K               

    D)               400 K

    Correct Answer: A

    Solution :

    \[W={{Q}_{1}}-{{Q}_{2}}\] \[W={{Q}_{2}}-{{Q}_{3}}\] \[{{Q}_{1}}-{{Q}_{2}}={{Q}_{2}}-{{Q}_{3}}\] \[{{T}_{1}}-T=T-{{T}_{3}}\] \[2T={{T}_{1}}-{{T}_{3}}\] \[T=\frac{{{T}_{1}}+{{T}_{3}}}{2}=500\,\,K\]                                   


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