A) four irrational numbers.
B) two irrational and one rational number.
C) four rational numbers.
D) two irrational and two rational numbers.
Correct Answer: B
Solution :
\[f'(x)=\lambda (x+1)(x-0)(x-1)=\lambda ({{x}^{3}}-x)\] \[\Rightarrow \]\[f(x)=\lambda \left( \frac{{{x}^{4}}}{4}-\frac{{{x}^{2}}}{2} \right)+\mu \] Now\[f(x)=f(0)\] \[\Rightarrow \lambda \left( \frac{{{x}^{4}}}{4}-\frac{{{x}^{2}}}{2} \right)+\mu =\mu \]\[\Rightarrow x=0,0,\pm \sqrt{2}\] Two irrational and one rational number
You need to login to perform this action.
You will be redirected in
3 sec
