JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer A wire of resistance R is bent to form a square ABCD as shown in the figure. The effective resistance between E and C is: (E is mid-point of arm CD)             [JEE Main 9-4-2019 Morning]

    A) \[R\]                            

    B) \[\frac{1}{16}R\]

    C) \[\frac{7}{64}R\]

    D) \[\frac{3}{4}R\]

    Correct Answer: C

    Solution :

    \[\frac{1}{{{R}_{eq}}}=\frac{8}{7R}+\frac{8}{R}\] \[\frac{1}{{{R}_{eq}}}=\frac{8+56}{7R}\] \[{{R}_{eq}}=\frac{7R}{64}\] Option [c]                   


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