• question_answer A wire of resistance R is bent to form a square ABCD as shown in the figure. The effective resistance between E and C is: (E is mid-point of arm CD)             [JEE Main 9-4-2019 Morning] A) $R$                            B) $\frac{1}{16}R$C) $\frac{7}{64}R$D) $\frac{3}{4}R$

$\frac{1}{{{R}_{eq}}}=\frac{8}{7R}+\frac{8}{R}$ $\frac{1}{{{R}_{eq}}}=\frac{8+56}{7R}$ ${{R}_{eq}}=\frac{7R}{64}$ Option [c]