JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer The correct order of the oxidation states of nitrogen in \[NO,{{N}_{2}}O,N{{O}_{2}}\]and \[{{N}_{2}}{{O}_{3}}\]is : [JEE Main 9-4-2019 Morning]

    A) \[N{{O}_{2}}<{{N}_{2}}{{O}_{3}}<NO<{{N}_{2}}O\]

    B) \[N{{O}_{2}}<NO<{{N}_{2}}{{O}_{3}}<{{N}_{2}}O\]

    C) \[{{N}_{2}}O<{{N}_{2}}{{O}_{3}}<NO<N{{O}_{2}}\]

    D) \[{{N}_{2}}O<NO<{{N}_{2}}{{O}_{3}}<N{{O}_{2}}\]

    Correct Answer: D

    Solution :

    Correct order of oxidation state of nitrogen in oxides of nitrogen is following \[\overset{+1}{\mathop{{{N}_{2}}}}\,O<\overset{+2}{\mathop{N}}\,O<\overset{+3}{\mathop{{{N}_{2}}}}\,{{O}_{3}}<\overset{+4}{\mathop{N}}\,{{O}_{2}}\]

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