JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer
    A rectangular coil (Dimension \[5cm\times 2.5cm)\] with 100 turns, carrying a current of 3 A in the clock-wise direction is kept centered at the origin and in the X-Z plane. A magnetic field of 1 T is applied along X-axis. If the coil is tilted through\[45{}^\circ \]about Z-axis, then the torque on the coil is : [JEE Main 9-4-2019 Morning]

    A) 0.55 Nm                     

    B) 0.27 Nm

    C) 0.38 Nm         

    D) 0.42 Nm

    Correct Answer: B

    Solution :

    \[\left| {\vec{\tau }} \right|=\left| \bar{M}\times \bar{B} \right|\]           \[\tau =NI\times A\times B\times \sin {{45}^{o}}\]           \[\tau =0.27Nm\] Option [b]


You need to login to perform this action.
You will be redirected in 3 sec spinner