A) 889.2 nm
B) 642.7 nm
C) 488.9 nm
D) 388.9 nm
Correct Answer: C
Solution :
\[\frac{1}{660}=R\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)=\frac{5R}{36}\] ....(1) \[\frac{1}{\lambda }=R\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{4}^{2}}} \right)=\frac{3R}{16}\] ....(2) divide equation (1) with (2) \[\frac{\lambda }{660}=\frac{5\times 16}{36\times 3}\] \[\lambda =\frac{4400}{9}=488.88=488.9nm\] Option [c]
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