JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer A body of mass 2 kg makes an eleastic collision with a second body at rest and continues to move in the original direction but with one fourth of its original speed. What is the mass of the second body? [JEE Main 9-4-2019 Morning]

    A) 1.8 kg              

    B) 1.2 kg

    C) 1.5 kg              

    D) 1.0 kg

    Correct Answer: B

    Solution :

    By conservation of linear momentum :- \[2{{\text{v}}_{0}}=2\left( \frac{{{\text{v}}_{0}}}{4} \right)+m\text{v}\Rightarrow \text{2}{{\text{v}}_{0}}=\frac{{{\text{v}}_{0}}}{2}+m\text{v}\] \[\Rightarrow \frac{\text{3}{{\text{v}}_{0}}}{2}=m\text{v}\]??.(1) Since collision is elastic\[\to \] \[{{\text{V}}_{\text{separation}}}\text{=}\,{{\text{v}}_{\text{approch}}}\] \[\Rightarrow \text{v-}\frac{{{\text{v}}_{0}}}{4}={{\text{v}}_{0}}\Rightarrow \frac{\text{5}{{\text{v}}_{0}}}{4}=\text{v}\]?..(2) equating (2) and (1) \[\frac{\text{3}{{\text{v}}_{0}}}{2}=m\left( \frac{\text{5}{{\text{v}}_{0}}}{4} \right)\Rightarrow \,=m=\frac{6}{5}=1.2kg\] Option [b]

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