JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Afternoon)

  • question_answer
    The domain of the definition of the function \[f(x)=\frac{1}{4-{{x}^{2}}}+{{\log }_{10}}({{x}^{3}}-x)\]is :-             [JEE Main 9-4-2019 Afternoon]

    A) \[(1,2)\cup (2,\infty )\]

    B) \[(-1,0)\cup (1,2)\cup (3,\infty )\]

    C) \[(-1,0)\cup (1,2)\cup (2,\infty )\]

    D) \[(-2,-1)\cup (-1,0)\cup (2,\infty )\]

    Correct Answer: C

    Solution :

    \[4-{{x}^{2}}\ne 0;{{x}^{3}}-x>0\]           \[x=\pm 2\]   \[x(x-1)(x+2)>0\]                     \[\therefore \]\[{{D}_{f}}\in (-1,0)\cup (1,2)\cup (2,\infty )\]


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