question_answer

All possible numbers are formed using the digits 1, 1, 2, 2, 2, 2, 3, 4, 4 taken all at a time. The number of such numbers in which the odd digits occupy even places is :                     [JEE Main 8-4-2019 Morning]

A) 175                 

B) 162

C) 160                 

D) 180

Correct Answer: D

Solution :

Number of such numbers  \[{{=}^{4}}{{C}_{3}}\times \frac{3!}{2!}\times \frac{6!}{2!4!}=180\]