JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    The magnitude of the projection of the vector \[2\hat{i}+3\hat{j}+\hat{k}\] on the vector perpendicular to the plane containing the vectors \[\hat{i}+\hat{j}+\hat{k}\] and \[\hat{i}+2\hat{j}+3\hat{k},\]is : [JEE Main 8-4-2019 Morning]

    A) \[\frac{\sqrt{3}}{2}\]                         

    B) \[\sqrt{\frac{3}{2}}\]

    C) \[\sqrt{6}\]                              

    D) \[3\sqrt{6}\]

    Correct Answer: B

    Solution :

    Vector perpendicular to plane containing the vectors \[\hat{i}+\hat{j}+\hat{k}\And \hat{i}+2\hat{j}+3\hat{k}\] is parallel to vector\[=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    1 & 1 & 1  \\    1 & 2 & 3  \\ \end{matrix} \right|=\hat{i}-2\hat{j}+\hat{k}\] \[\therefore \] Required magnitude of projection \[=\frac{\left| (2\hat{i}+3\hat{j}+\hat{k}).(\hat{i}-2\hat{j}+\hat{k}) \right|}{\left| \hat{i}-2\hat{j}+\hat{k} \right|}\] \[=\frac{\left| 2-6+1 \right|}{\left| \sqrt{6} \right|}=\frac{3}{\sqrt{6}}=\sqrt{\frac{3}{2}}\]


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