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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    For silver, \[{{C}_{p}}\left( J{{K}^{-1}}mo{{l}^{-1}} \right)=23+0.01T\]. If the temperature (T) of 3 moles of silver is raised from 300K to 1000 K at 1 atm pressure, the value of \[\Delta H\] will be close to [JEE Main 8-4-2019 Morning]

    A) 21 kJ               

    B) 16 kJ

    C) 13 kJ               

    D) 62 kJ

    Correct Answer: D

    Solution :

    \[\Delta H=n\int\limits_{{{T}_{1}}}^{{{T}_{2}}}{{{C}_{p.m}}dT}=3\times \int\limits_{300}^{1000}{(23+0.01T)dT}\]           \[=3[23(1000-300)+\frac{0.01}{2}({{1000}^{2}}-{{300}^{2}})]\]           \[=61950\,J\approx 62kJ\] Correct option : (d)


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