A) \[S={{\left( \frac{{{K}_{sp}}}{929} \right)}^{1/9}}\]
B) \[S={{\left( \frac{{{K}_{sp}}}{216} \right)}^{1/7}}\]
C) \[S={{\left( \frac{{{K}_{sp}}}{144} \right)}^{1/6}}\]
D) \[S={{\left( \frac{{{K}_{sp}}}{6912} \right)}^{1/7}}\]
Correct Answer: D
Solution :
\[Z{{r}_{3}}{{(P{{O}_{4}})}_{4}}(s)3Z{{r}^{4+}}(aq.)+4PO_{4}^{3-}(aq.)\] \[{{K}_{sp}}={{[Z{{r}^{4+}}]}^{3}}{{[P{{O}_{4}}^{3-}]}^{4}}\overset{3SM}{\mathop{={{(3S)}^{3}}.}}\,\overset{4SM}{\mathop{{{(4S)}^{4}}=6912}}\,{{S}^{7}}\] \[\therefore \]\[S:{{\left( \frac{{{K}_{sp}}}{6912} \right)}^{1/7}}\]
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