A) 4
B) 2
C) 9
D) 18
Correct Answer: A
Solution :
Given\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{3}\] Ratio of intensities,\[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{{{a}_{1}}}{{{a}_{2}}} \right)}^{2}}=\frac{1}{9}\] Now,\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}}}{\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}}} \right)}^{2}}={{\left( \frac{1+3}{1-3} \right)}^{2}}=4\]
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