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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    The tangent to the parabola \[{{y}^{2}}=4x\]at the point where it intersects the circle \[{{x}^{2}}+{{y}^{2}}=5\]in the first quadrant, passes through the point: [JEE Main 8-4-2019 Afternoon]

    A) \[\left( -\frac{1}{3},\frac{4}{3} \right)\]

    B)               \[\left( -\frac{1}{4},\frac{1}{2} \right)\]

    C) \[\left( \frac{3}{4},\frac{7}{4} \right)\]

    D)   \[\left( \frac{1}{4},\frac{3}{4} \right)\]

    Correct Answer: C

    Solution :

                Given \[{{y}^{2}}=4x\]                               ...(1) and\[{{x}^{2}}+{{y}^{2}}=5\]                                      ...(2) by and \[\Rightarrow x=1\]and y = 2 equation of tangent at (1,2) to \[{{y}^{2}}=4x\]is \[y=x+1\]


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