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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    If the system of linear equations
    \[x2y+kz=1\]
    \[2x+y+z=2\]
    \[3xykz=3\]
    has a solution \[(x,y,z),z\ne 0,\]then (x,y) lies on the straight line whose equation is :
    [JEE Main 8-4-2019 Afternoon]

    A) \[3x4y1=0\]    

    B) \[3x4y4=0\]

    C) \[4x3y4=0\]

    D) \[4x3y1=0\]

    Correct Answer: C

    Solution :

     \[x2y+kz=1\]                         ...(1) \[2x+y+z=2\]                                     ...(2) \[3xykz=3\]                              ...(3) (1) + (3) \[\Rightarrow 4x3y=4\]          


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