A) \[6.6\,\times {{10}^{-5}}\,gm\]
B) \[0.96\,gm\]
C) \[4\times {{10}^{-2}}\,gm\]
D) \[0.8\,gm\]
Correct Answer: C
Solution :
\[P=\frac{E}{\Delta t}\,=\frac{\Delta m{{c}^{2}}}{\Delta t}\] \[\frac{\Delta m}{\Delta t}=\frac{P}{{{c}^{2}}}\,=\frac{{{10}^{9}}}{{{(3\times {{10}^{8}})}^{2}}}=4\times {{10}^{-2}}\,gm\]
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