A) one-one but not onto
B) one-one and onto
C) neither one-one nor onto
D) onto but not one-one
Correct Answer: C
Solution :
\[\left. \begin{align} & f(1)=1-5\,(1/5)=1 \\ & f(6)=6-6[6/5]=1 \\ \end{align} \right\}\to \] Many one \[f(10)\,=10-5(2)=0\] which is not in coduman many one + into
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