A) 74
B) 53
C) 56
D) 65
Correct Answer: C
Solution :
P(4, 7) it midpoint the circle \[PA\,\,PB=\,s_{1}^{2}\,=P{{T}^{2}}\] \[{{s}_{1}}=\sqrt{16+49-9}\,=\sqrt{56}\] \[S_{1}^{2}=56;\,\,\,\,\,\,\,\,\,\,PA-PB=56\]
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