A) 0.56 nm
B) 0.24 nm
C) 0.96 nm
D) 0.4 nm
Correct Answer: D
Solution :
For fee unit cell, \[r=\frac{\sqrt{2}}{4}a\] \[0.14=\frac{\sqrt{2}}{4}a\] \[a=\frac{4\times 0.1}{\sqrt{2}}=0.396=0.4\,\,\text{nm}\]
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