question_answer

                Anether (A) \[{{\operatorname{C}}_{5}}{{\operatorname{H}}_{12}}\operatorname{O},\]when heated with excess of hot concentrated HI produced two alky halides which when treated with NaOH yielded compounds (B) and (C) Oxidation of (B) and (C) gave a propanone and an ethanoic acid respectively. The IUPAC name of the ether (A) is:           JEE Main Online Paper (Held On 09 April 2013)        

A)                 2-ethoxypropane                

B)                 ethoxypropane                

C)                 methoxybutane                

D)                        2-methoxybutane                

Correct Answer: A

Solution :

                 Ether (A) is 2-ethoxypropane \[{{C}_{3}}{{H}_{7}}-O-{{C}_{2}}{{H}_{5}}\]