A) \[{{2}^{0}}>{{1}^{0}}>{{\operatorname{CH}}_{3}}\operatorname{OH}>{{3}^{0}}\]
B) \[{{3}^{0}}>{{2}^{0}}>{{1}^{0}}{{\operatorname{CH}}_{3}}\operatorname{OH}\]
C) \[{{2}^{0}}>{{3}^{0}}>{{1}^{0}}{{\operatorname{CH}}_{3}}\operatorname{OH}\]
D) \[{{\operatorname{CH}}_{3}}\operatorname{OH}>{{1}^{0}}>{{2}^{0}}>{{3}^{0}}\]
Correct Answer: B
Solution :
Dehydration of alcohols takes place according to Saytzeff rule. In acid, catalysed dehydration formation of most stable carbocation takes place. Thus, the order of dehydration of alcohols is \[{{3}^{0}}>{{2}^{0}}>{{1}^{0}}>C{{H}_{3}}OH\]
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