A) \[[M]=[{{T}^{-1}}{{C}^{-2}}h]\]
B) \[[M]=[T{{C}^{-2}}h]\]
C) \[[M]=[{{T}^{-1}}{{C}^{-2}}{{h}^{-1}}]\]
D) \[[M]=[{{T}^{-1}}{{C}^{2}}h]\]
Correct Answer: A
Solution :
\[M\propto {{T}^{x}}{{v}^{y}}{{h}^{z}}\] \[M'{{L}^{0}}{{T}^{0}}={{(T')}^{x}}{{({{L}^{1}}{{T}^{-1}})}^{y}}{{({{M}^{1}}{{L}^{2}}{{T}^{-1}})}^{z}}\] \[{{M}^{1}}{{L}^{0}}{{T}^{0}}={{M}^{z}}{{L}^{y+2z}}+{{T}^{x-y-z}}\] \[z=1\] \[y+2z=0\] \[x-y-z=0\] \[y=-2\] \[x+2-1=0\] \[x=-1\] \[M\Rightarrow {{T}^{-1}}{{C}^{-2}}{{h}^{1}}\]
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