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JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    The coordinates of the foot of the perpendicular from the point (1, - 2,1) on the plane containing the lines, \[\frac{x+1}{6}=\frac{y-1}{7}=\frac{z-3}{8}\]and \[\frac{x-1}{3}=\frac{y-2}{5}=\frac{z-3}{7},\]is: [JEE Online 08-04-2017]

    A)  (2, - 4, 2)                            

    B)  (1, 1, 1)

    C)  (0, 0, 0)                               

    D)  (0, 0, 0)

    Correct Answer: C

    Solution :

    \[\overline{n}={{\overline{n}}_{1}}\times {{\overline{n}}_{2}}\] \[=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    6 & 7 & 8  \\    3 & 5 & 7  \\ \end{matrix} \right|\] \[=(9,-18,9)\] \[=(1,-2,1)\] \[1(x+1)-2(y-1)+(2-3)=0\] \[=\]foot to z \[\frac{x-1}{1}=\frac{y+2}{-2}=\frac{z-1}{1}=\frac{[1+4+1]}{6}\] \[\]10,000


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