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JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    What is the ­­\[\operatorname{p}\operatorname{H}\] of a\[{{10}^{-4}}\] M \[{{\operatorname{OH}}^{-}}\] solution at \[330\operatorname{K},\] if \[{{\operatorname{K}}_{w}}\]at 330K is \[{{10}^{-13.6}}?\]     JEE Main Online Paper ( Held On 23  April 2013 )

    A)                   4                                           

    B)                                          9.0

    C)                                          10                                        

    D)                                          9.6

    Correct Answer: D

    Solution :

                      Given at 330 K \[{{K}_{w}}={{10}^{-13.6}}\] i.e.\[p{{K}_{w}}=pH+pOH\] \[\because \]\[pOH=-\log [O{{H}^{-}}]\] \[\text{13}.\text{6}=\text{pH}+\text{pOH}\] \[=-\log {{10}^{-4}}\] \[=pH+4\] \[=4\] \[\therefore \]\[pH=13.6-4\] \[=9.6\]


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