A) \[\operatorname{Be}{{\operatorname{CI}}_{2}}\]
B) \[\operatorname{Sr}{{\operatorname{CI}}_{2}}\]
C) \[\operatorname{Ca}{{\operatorname{CI}}_{2}}\]
D) \[{{\operatorname{M}}_{g}}{{\operatorname{CI}}_{2}}\]
Correct Answer: A
Solution :
Metal halide on hydrolysis with water form corresponding hydroxides. - The basic strength of hydroxide increases as we move down in a group. This is because of the increase in size which results in decrease of ionizatibn energy which weakens the strength of M - O bonds in MOH and thus increases the basic strength. \[\underset{Amphoteric}{\mathop{Be{{(OH)}_{2}}}}\,\underset{Weak\,base}{\mathop{Mg{{(OH)}_{2}}}}\,\] \[Ca{{(OH)}_{2}}\underset{Strong\,base}{\mathop{Sr{{(OH)}_{2}}}}\,Ba{{(OH)}_{2}}\] Hence, \[Be{{(OH)}_{2}}\]will have lowest pH.
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