A) \[\theta \]increases and h also increases
B) \[\theta \]decreases and h also decreases
C) \[\theta \]increases and h decreases
D) \[\theta \]decreases and h increases
Correct Answer: C
Solution :
Angle of contact \[\cos \theta =\frac{{{T}_{SA}}-{{T}_{SL}}}{{{T}_{LA}}}\]when water is on a waxy or oily surface \[{{T}_{SA}}<{{T}_{SL}}\cos \theta \]is negative i.e.,\[{{90}^{o}}<\theta <{{180}^{o}}\]i.e., angle of contact \[\theta \]increases And for \[\theta >{{90}^{o}}\] liquid level in capillary tube fall. i.e., h decreases
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