A) \[2{{P}_{A}}=3{{P}_{B}}\]
B) \[3{{P}_{A}}=2{{P}_{B}}\]
C) \[{{P}_{A}}=2{{P}_{B}}\]
D) \[{{P}_{A}}=3{{P}_{B}}\]
Correct Answer: A
Solution :
\[{{Z}_{A}}=\frac{{{P}_{A}}{{V}_{A}}}{nR{{T}_{A}}},{{Z}_{B}}=\frac{{{P}_{B}}{{V}_{B}}}{nR{{T}_{B}}}\] Given,\[{{T}_{A}}={{T}_{B}}\] n = same \[{{V}_{A}}=2{{V}_{B}}\] \[{{Z}_{A}}=3{{Z}_{B}}\] Then,\[{{Z}_{A}}=\frac{{{P}_{A}}\times 2{{V}_{B}}}{nR{{T}_{A}}}=3{{Z}_{B}}=\frac{3{{P}_{B}}{{V}_{B}}}{nR{{T}_{B}}}\] \[{{P}_{A}}\times 2{{V}_{B}}=3{{P}_{B}}{{V}_{B}},2{{P}_{A}}=3{{P}_{B}}\]
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