| \[{{A}_{(s)}}{{B}_{(g)}}+{{C}_{(g)}};{{K}_{P1}}=x\,at{{m}^{2}}\] |
| \[{{D}_{(s)}}{{C}_{(g)}}+{{E}_{(g)}};{{K}_{P2}}=y\,at{{m}^{2}}\] |
A) \[\sqrt{x+y}atm\]
B) \[{{x}^{2}}+{{y}^{2}}atm\]
C) \[2\left( \sqrt{x+y} \right)atm\]
D) \[(x+y)atm\]
Correct Answer: C
Solution :
\[{{A}_{(s)}}\underset{{{P}_{1}}}{\mathop{{{B}_{(g)}}}}\,+\underset{{{P}_{1}}+{{P}_{2}}}{\mathop{{{C}_{(g)}}}}\,\] \[{{D}_{(s)}}\underset{{{P}_{1}}+{{P}_{2}}}{\mathop{{{C}_{(g)}}}}\,+\underset{{{P}_{2}}}{\mathop{{{E}_{(g)}}}}\,\] \[{{K}_{{{P}_{1}}}}=x={{P}_{1}}({{P}_{1}}+{{P}_{2}})at{{m}^{2}},{{K}_{{{P}_{2}}}}=y={{P}_{2}}({{P}_{1}}+{{P}_{2}})at{{m}^{2}}\] \[x+y={{({{P}_{1}}+{{P}_{2}})}^{2}}\Rightarrow {{P}_{1}}+{{P}_{2}}=\sqrt{x+y}\] \[{{P}_{Total}}={{P}_{B}}+{{P}_{C}}+{{P}_{E}}=2({{P}_{1}}+{{P}_{2}})=2\sqrt{x+y}atm\]
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