question_answer

Shown in the figure is a shell made of a conductor. It has inner radius a and outer radius b, and carries charge Q. At its centre is a dipole \[\vec{p}\] as shown. In this case:                                                     [JEE Main Held on 12-4-2019 Morning]

A) Electric field outside the shell is the same as that of a point charge at the centre of the shell.

B) Surface charge density on the inner surface of the shell is zero everywhere.

C) Surface charge density on the inner surface is uniform and equal to \[\frac{(Q/2)}{4\pi {{a}^{2}}}.\]

D) Surface charge density on the outer surface depends on \[\left| {\vec{p}} \right|\]

Correct Answer: A

Solution :

Total charge of dipole = 0, so charge induced on outside surface = 0. But due to non uniform electric field of dipole, the charge induced on inner surface is non zero and non uniform. So, for any abserver outside the shell, the resultant electric field is due to Q uniformly distributed on outer surface only and it is equal to.  \[\]