question_answer

To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained:

If V0 is almost zero, identify the correct statement:

                                                                                                [JEE Main Held on 12-4-2019 Morning]

A) The value of the resistance R is \[1.5\Omega \]

B) The emf of the battery is 1.5 V and the value of R is \[1.5\Omega \]

C) The emf of the battery is 1.5 V and its internal resistance is \[1.5\Omega \]

D) The potential difference across the battery is 1.5 V when it sends a current of 1000 mA.

Correct Answer: C

Solution :

\[V=E-Ir\]when \[V={{V}_{0}}=0\Rightarrow 0=E-Ir\] \[\therefore \]E = r when \[I=0,V=E=1.5V\] \[\therefore \] \[r=1.5\Omega .\]