A) \[\left| \begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \end{matrix} \right|\]
B) \[\left| \begin{matrix} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \end{matrix} \right|\]
C) \[\left| \begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \end{matrix} \right|\]
D) \[\left| \begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \end{matrix} \right|\]
Correct Answer: A
Solution :
\[C=A+B\]and \[y=\overline{A.C}\]\[A\] | \[B\] | \[C=(A+B)\] | \[A.C.\] | \[y=\overline{A.C}\] |
0 | 0 | 0 | 0 | 1 |
0 | 1 | 1 | 0 | 1 |
1 | 0 | 1 | 1 | 0 |
1 | 1 | 1 | 1 | 0 |
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