A) 20g of carbon and 5 g of hydrogen
B) 24g of carbon and 1 g of hydrogen
C) 18g of carbon and 7 g of hydrogen
D) 22g of carbon and 3 g of hydrogen
Correct Answer: B
Solution :
\[{{C}_{x}}{{H}_{y}}+\left( x+\frac{y}{4} \right){{O}_{2}}\xrightarrow[{}]{{}}xC{{O}_{2}}+\frac{y}{2}{{H}_{2}}O\] \[\left( \frac{25}{M} \right)\] \[\begin{matrix} \underset{=2}{\mathop{x\times \left( \frac{25}{M} \right)}}\, & \underset{=\,0.5}{\mathop{\frac{y}{2}\times \frac{25}{M}}}\, \\ \end{matrix}\] \[C\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\times \frac{25}{M}=2\] \[H\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y\times \frac{25}{M}=1\] \[{{C}_{2y}}{{H}_{y}}\equiv 24y\,gm\,C+y\,gm\,H\] Or 24:1 ratio by mass
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