[JEE Main Online Paper (Held On 10-Jan-2019 Morning]
A) \[\frac{m{{g}^{2}}{{t}^{2}}}{8}\]
B) \[\frac{3\,m{{g}^{2}}{{t}^{2}}}{8}\]
C) \[-\frac{\,m{{g}^{2}}{{t}^{2}}}{8}\]
D) 0
Correct Answer: B
Solution :
\[N=m\left( g+\frac{g}{2} \right)\,=\,\frac{3mg}{2}\] \[S\,=\,\frac{1}{2}\,\,\times \,\,\frac{g}{2}{{t}^{2}}\] Work done \[=\,\,\frac{3mg}{2}\,\,\times \,\frac{g}{4}{{t}^{2}}\,=\,\frac{3m{{g}^{2}}}{8}{{t}^{2}}\]
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