A) \[x-y+9=0\]
B) \[x-y-3=0\]
C) \[x-y+1=0\]
D) \[x-y+7=0\]
Correct Answer: C
Solution :
\[\frac{{{x}^{2}}}{5}-\frac{{{y}^{2}}}{4}\,\,=\,\,1\] \[x-y=2\text{ }\] \[y=mx\pm \sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}}~~~~~m=1\] \[y=x\pm \sqrt{5-4}\] \[x-y\pm 1=0\]
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