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JEE Main & Advanced JEE Main Online Paper (Held On 08 April 2018)

  • question_answer
    When metal M is treated with NaOH, a white gelatinous precipitate X is obtained, which is soluble in excess of \[\text{NaOH}\] Compound X when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal M is:                   [JEE Main Online 08-04-2018]

    A)  Al                               

    B)  Fe

    C)  Zn                              

    D)  Ca

    Correct Answer: A

    Solution :

    According to given question \[\text{Al(s)+NaOH(aq)}\xrightarrow{{}}\underset{\begin{smallmatrix}  \text{      White} \\  \text{gelatinous}\,\,\text{ppt} \end{smallmatrix}}{\overset{\text{(X)}}{\mathop{\text{Al(OH}{{\text{)}}_{\text{3}}}}}}\,\downarrow \xrightarrow{\text{Excess NaOH}}\underset{\text{Soluble}}{\mathop{\text{Na }\!\![\!\!\text{ Al(OH}{{\text{)}}_{\text{4}}}\text{ }\!\!]\!\!\text{ }}}\,\] Compound \[\text{(X)}\xrightarrow{{}}\text{Al(OH}{{\text{)}}_{\text{3}}}\] on heating gives \[\text{A}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]which is used in chromatography as an adsorbent. Thus metal M is aluminium (Al).


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