JEE Main & Advanced JEE Main Online Paper (Held On 08 April 2018)

  • question_answer
    An aqueous solution contains an unknown concentration of \[\text{B}{{\text{a}}^{\text{2+}}}\]. When 50 mL of a 1 M solution of \[\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\] is added, \[\text{BaS}{{\text{O}}_{4}}\] just begins to precipitate. The final volume is 500 mL. The solubility product of \[\text{BaS}{{\text{O}}_{4}}\] is\[1\times {{10}^{-10}}\].  What is the original concentration of \[B{{a}^{2+}}?\]    [JEE Main Online 08-04-2018]

    A)  \[1.1\times {{10}^{-9}}\,\,M\]                    

    B)  \[1.0\times {{10}^{-10}}\,\,M\]

    C)  \[5\times {{10}^{-9}}\,\,M\]           

    D)  \[2\times {{10}^{-9}}\,\,M\]

    Correct Answer: A

    Solution :

    \[\text{BaS}{{\text{O}}_{\text{4}}}\text{(s)}\text{B}{{\text{a}}^{\text{2+}}}\text{(aq)+S}{{\text{O}}_{\text{4}}}^{\text{2-}}\text{(aq)}\] \[\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{(aq)}\xrightarrow{{}}\text{2N}{{\text{a}}^{\text{2+}}}\text{(aq)+S}{{\text{O}}_{\text{4}}}^{\text{2-}}\text{(aq)}\] \[\frac{1\times 50}{500}=0.1M\] \[{{\text{K}}_{\text{sp}}}\text{= }\!\![\!\!\text{ B}{{\text{a}}^{\text{2+}}}{{\text{ }\!\!]\!\!\text{ }}_{\text{final}}}{{\text{ }\!\![\!\!\text{ S}{{\text{O}}_{\text{4}}}^{\text{2-}}\text{ }\!\!]\!\!\text{ }}_{\text{final}}}\] \[\text{1}\times {{10}^{-10}}=\left( {{[B{{a}^{+2}}]}_{initial}}\times \frac{450}{500} \right)\times [0.1]\] \[\text{ }\!\![\!\!\text{ B}{{\text{a}}^{\text{2+}}}\text{ }\!\!]\!\!\text{ =1}\text{.1 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-9}}}\text{M}\]


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