A) \[\text{3}\text{.2 hours}\]
B) \[\text{1}\text{.6 hours}\]
C) \[\text{6}\text{.4 hours}\]
D) \[\text{0}\text{.8 hours}\]
Correct Answer: A
Solution :
\[{{B}_{2}}{{H}_{6}}+3{{O}_{2}}(g)\xrightarrow{{}}{{B}_{2}}{{O}_{3}}+3{{H}_{2}}O(\ell )\] moles\[=\frac{27.66}{27.6}=1\] 1mole of \[{{\text{B}}_{\text{2}}}{{\text{H}}_{\text{6}}}\] required 3 moles of \[{{\text{O}}_{2}}\] \[2{{H}_{2}}O(\ell )\xrightarrow{{}}{{O}_{2}}(g)+4{{H}^{+}}(aq)+4{{e}^{-}}\] \[\frac{It}{96500}=\]mole of \[{{O}_{2}}\times {{n}_{f}}\] \[\frac{100\times t\times 3600}{96500}=3\times 4\Rightarrow t=3.2hrs\]
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