A) \[2\times {{10}^{5}}\]
B) \[2\times {{10}^{6}}\]
C) \[2\times {{10}^{3}}\]
D) \[2\times {{10}^{4}}\]
Correct Answer: A
Solution :
Carrie Frequency\[\text{=10 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{9}}}\text{Hz}\] \[\text{10 }\!\!%\!\!\text{ is utilised=}\frac{10}{100}\times 10\times {{10}^{9}}\] \[={{10}^{9}}Hz\] Band width \[=5k\,\,Hz\] No. of channel required\[=\frac{{{10}^{9}}}{5\times {{10}^{3}}}\] \[=2\times {{10}^{5}}\]
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