A) \[\text{2}\text{.4 n C}\]
B) \[\text{0}\text{.9 n C}\]
C) \[\text{1}\text{.2 n C}\]
D) \[\text{0}\text{.3 n C}\]
Correct Answer: C
Solution :
\[q=CV=3\times {{10}^{-9}};here\,\,C=K{{C}_{0}}\] \[{{q}_{ind}}=3\times {{10}^{-9}}\left( 1-\frac{1}{K} \right)\] \[{{q}_{ind}}=3\times {{10}^{-9}}\left( 1-\frac{3}{5} \right)=3\times {{10}^{-9}}\times \frac{2}{5}\] \[{{q}_{ind}}=1.2\times {{10}^{-9}}\]
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