A) \[{{r}_{e}}<{{r}_{p}}<{{r}_{\alpha }}\]
B) \[{{r}_{e}}<{{r}_{\alpha }}<{{r}_{p}}\]
C) \[{{r}_{e}}>{{r}_{p}}={{r}_{\alpha }}\]
D) \[{{r}_{e}}<{{r}_{p}}={{r}_{\alpha }}\]
Correct Answer: D
Solution :
\[r=\frac{mv}{Bq}=\frac{\sqrt{2mk}}{Bq}\] \[\frac{{{r}_{p}}}{{{r}_{e}}}=\frac{\sqrt{{{m}_{p}}}}{\sqrt{{{m}_{e}}}}\] \[{{m}_{p}}>{{m}_{e}}\] \[{{r}_{p}}>{{r}_{e}}\] \[\frac{{{r}_{p}}}{{{r}_{\alpha }}}=\frac{\sqrt{{{m}_{p}}}}{{{q}_{p}}}\frac{2{{q}_{p}}}{\sqrt{4{{m}_{p}}}}=1\] \[{{r}_{p}}={{r}_{\alpha }}\]
You need to login to perform this action.
You will be redirected in
3 sec
