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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    If the eccentricity of the standard hyperbola passing through the point (4,6) is 2, then the equation of the tangent to the hyperbola at (4,6) is- [JEE Main 8-4-2019 Afternoon]

    A) \[2xy2=0\]

    B) \[3x2y=0\]

    C) \[2x3y+10=0\]

    D)   \[x2y+8=0\]

    Correct Answer: A

    Solution :

    Let us Suppose equation of hyperbola is \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1\] \[e=2\Rightarrow {{b}^{2}}=3{{a}^{2}}\] passing through\[(4,6)\Rightarrow {{a}^{2}}=4,{{b}^{2}}=12\] \[\Rightarrow \]equation of tangent \[x-\frac{y}{2}=1\]\[\Rightarrow \]\[2x-y-2=0\]


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