JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    For a reaction scheme \[A\xrightarrow[{}]{{{k}_{1}}}B\xrightarrow[{}]{{{k}_{2}}}C,\] if the rate of formation of B is set to be zero then the concentration of B is given by: [JEE Main 8-4-2019 Afternoon]

    A) \[\left( \frac{{{k}_{1}}}{{{k}_{2}}} \right)[A]\]     

    B) \[({{k}_{1}}+{{k}_{2}})[A]\]

    C) \[{{k}_{1}}{{k}_{2}}[A]\]  

    D)   \[({{k}_{1}}-{{k}_{2}})[A]\]

    Correct Answer: A

    Solution :

    \[A\xrightarrow[{}]{{{K}_{1}}}B\xrightarrow[{}]{{{K}_{2}}}C\]           \[\frac{d[B]}{dt}=0={{K}_{1}}[A]-{{K}_{2}}[B]\]\[\Rightarrow \]\[[B]=\frac{{{K}_{1}}}{{{K}_{2}}}[A]\]        


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